Время науки - The Times of Science

Ермолицкая А. Д. Ermolitskaya A. D. 2025 9 + − (2 3 ′ cos 1 + 2 3 ′ sin 1 ) + (2 4 ′ cos 1 − 2 4 ′ sin 1 ) where 1 = 1 ( 1 ) 2 ′ ( 1 ) , 2 = 1 ( 2 ) 2 ′ ( 2 ) , 3 = 1 ( 3 ) 2 ′ ( 3 ) , 4 = 1 ( 4 ) 2 ′ ( 4 ) 1 = 1 ( 1 ) 2 ′ ( 1 ) , 2 = 1 ( 2 ) 2 ′ ( 2 ) , 3 = 1 ( 3 ) 2 ′ ( 3 ) , 4 = 1 ( 4 ) 2 ′ ( 4 ) 2 ′ = 1 ( 1 ) 2 ′ ( 1 ) , 2 ′ = 1 ( 2 ) 2 ′ ( 2 ) , 3 ′ = 1 ( 3 ) 2 ′ ( 3 ) , 4 ′ = 1 ( 4 ) 2 ′ ( 4 ) 1 ′ = 1 ( 1 ) 2 ′ ( 1 ) , 2 ′ = 1 ( 2 ) 2 ′ ( 2 ) , 3 ′ = 1 ( 3 ) 2 ′ ( 3 ) , 4 ′ = 1 ( 4 ) 2 ′ ( 4 ) The solution of the system (10) will have the form: where  ( ) and  ( ) are partial solutions of equations (10). The partial solutions of equations  ( ) and  ( ) , satisfy the conditions: Similarly, we find the analytical solution when the left end is pinched. Then the boundary conditions take the form: (0) = 0; ′ (0) = 0; (0) = 0; ′ (0) = 0; (27) with { ′′ (0) = 3 ; ′′′ (0) = 4 ; ′′ (0) = 3 ; ′′′ (0) = 4 ; (28) where 3 , 4 , 3 , 4 are arbitrary constants. After calculations we obtain the general solution of the system to find ( ) and ( ) : 1 ( ) = − (2 1 cos 1 + 2 1 sin 1 ) + (2 2 cos 1 − 2 2 sin 1 )